Octal to Binary Converter
Octal to Binary Converter. Type your value into Octal Input and the Octal to Binary Converter instantly expands it into Binary Output. Paste your hex bytes into the hex to base64 converter and the encoded Base64 string appears in the output box automatically.
Need the bits behind a base 8 value? This octal to binary converter turns every octal digit into a three-bit group, so a number like 3615 becomes 011 110 001 101 without any arithmetic on your part. Below, you will see how the octal to binary conversion works, why the direct route is so quick, and how to double-check an answer by hand.
How the Octal to Binary Converter Works
A calculator for octal values takes a number written in base 8, which uses only the symbols 0 to 7, and returns the same quantity in base 2. Because 8 is 23, each octal digit lines up with exactly three binary digits, so the job is a lookup rather than a long calculation. The decimal to hex converter takes any base-10 number and returns its exact hexadecimal equivalent, with an uppercase option for A-F formatting.
That is why a good converter shows its work next to the answer. You enter the octal value, press the convert button, and read the binary string. The conversion tool also lets you verify the output: split the answer into groups of three and compare each group with the table in the next section. A converter that hides this logic gives you a number but no way to trust it.
Octal to Binary Number Systems: Base 8 and Base 2
Before you convert octal to binary, know what each side of the conversion is. Both are positional systems, so the place of a digit decides how much it is worth. The hex shift calculator lets you pick a direction from a dropdown, set a shift amount, and calculate the resulting hex value in one step.
The Octal Number System
The octal number system has a radix of 8. It uses only the digits 0 to 7, and 8 and 9 never appear. Moving one place left multiplies a value by 8, so the rightmost place counts ones, the next counts eights, then sixty-fours. Writing the base as a subscript, such as 178, removes any doubt about which numeral system you mean.
The Binary Number System
The binary number system is base 2, with only the digits 0 and 1. Each binary digit is a single bit, and binary is a positional system too: every place is worth one of the powers of 2, namely 1, 2, 4, 8, 16 and on. Electronics favors it because a circuit only has to tell an electric signal that is off (0) from one that is on (1), and all digital data is stored that way as binary code.
How to Convert Octal to Binary with the Direct Method
The direct method is the fastest way to convert octal to binary. Replace every digit with its 3-bit word, keep the order, and join the groups. No division and no powers of 8 are needed. Use the hex to ral converter for a rough RAL name suggestion when you only have a hex code to work from, keeping in mind it's an unofficial approximation.
Octal to Binary Conversion Table
Memorize this conversion table and you can do the entire job in your head. The same eight rows work for every octal value of any length, and this binary equivalent table is the only reference you need.
| Octal digit | 3-bit binary | Decimal value |
|---|---|---|
| 0 | 000 | 0 |
| 1 | 001 | 1 |
| 2 | 010 | 2 |
| 3 | 011 | 3 |
| 4 | 100 | 4 |
| 5 | 101 | 5 |
| 6 | 110 | 6 |
| 7 | 111 | 7 |
Octal to Binary Conversion Steps
Follow these conversion steps for any whole octal number:
- Write the number and separate it into single symbols, starting at the lowest digit if you prefer to work right to left.
- Convert each digit by looking it up in the table and writing its binary word, three bits long.
- Place the words side by side in the same order, from the leftmost group to the rightmost.
- Remove any leading zeros. What remains is the binary number.
Why does grouping by three work? Octal and binary are both base numbers built on powers of 2, and since 8 = 23, a three-bit group can hold exactly the values 0 to 7. Inside a group the bits are worth 4, 2 and 1, so a word \(b_2 b_1 b_0\) always equals \(4b_2 + 2b_1 + b_0\), the same number as its octal digit. Take 6: it is 4 + 2 + 0, which is 110. No group ever carries into its neighbor, so the result of joining the groups is exact, and the same logic runs backward when you turn a binary string into octal by splitting it into threes from the right. This is also why the direct route never needs a remainder table.
Octal to Binary Conversion Steps: A Worked Example
Take the octal number 36158. It has four digits, so the output has up to 12 bits. Each row below applies the table to one symbol.
| Octal digit | Binary equivalent |
|---|---|
| 3 | 011 |
| 6 | 110 |
| 1 | 001 |
| 5 | 101 |
Joining the words gives 011110001101. Dropping the leading zero leaves 111100011012, so 36158 = 111100011012. That is an 11-bit binary value, one shorter than the groups suggest, because the first 0 carries no weight.
Octal to Binary Conversion with the Indirect Method
The indirect method goes through decimal. It is slower, but it is a useful cross-check and the route most textbooks teach first.
Octal to Decimal
Multiply each symbol by the power of 8 for its position, counting from 0 at the right, and sum up the products:
$$N_{10} = \sum d_i \times 8^{i}$$For 36158: \(3 \times 8^{3} + 6 \times 8^{2} + 1 \times 8^{1} + 5 \times 8^{0} = 1536 + 384 + 8 + 5 = 1933\). Each power of 8 is the place value of its position, which is what makes the system positional.
Decimal to Binary
Now divide the decimal value by 2 repeatedly. Write down each remainder, keep the quotient, and stop when the quotient reaches 0. Then read the remainders in reverse order.
| Divide by 2 | Quotient | Remainder |
|---|---|---|
| 1933 ÷ 2 | 966 | 1 |
| 966 ÷ 2 | 483 | 0 |
| 483 ÷ 2 | 241 | 1 |
| 241 ÷ 2 | 120 | 1 |
| 120 ÷ 2 | 60 | 0 |
| 60 ÷ 2 | 30 | 0 |
| 30 ÷ 2 | 15 | 0 |
| 15 ÷ 2 | 7 | 1 |
| 7 ÷ 2 | 3 | 1 |
| 3 ÷ 2 | 1 | 1 |
| 1 ÷ 2 | 0 | 1 |
Read from the bottom up, the remainders spell 11110001101, matching the direct route. When both agree, you can trust the answer.
An Online Tool for Octal to Binary Number Conversion
A free online tool saves time when the input is long. Type the octal numbers you have, such as 7406, press the convert button, and the converter returns the equivalent binary number: 111 100 000 110. To verify it, sum up the place values of the 1s: 2048 + 1024 + 512 + 256 + 4 + 2 = 3846, and 74068 is also 3846 in decimal, so the two agree.
Binary numbers get long quickly, which is why people read them in groups. A few quick facts help you sanity-check any output: octal 1000 expands to 001 000 000 000, which is 512 in decimal, and the largest single symbol, 7, is always 111. There is no special conversion formula to memorize, since by definition each octal symbol is just a shorthand for three bits.
Octal to Binary Conversion for a 12-Switch Panel
Dana is restoring a 1970s minicomputer whose front panel has twelve toggle switches, and the maintenance manual lists a bootstrap loader address as 52718. The switches are binary, so the manual's octal figure has to become a pattern of up and down toggles before anything gets loaded.
Dana types 5271 into the converter and watches it map the four octal digits to 101, 010, 111 and 001. The output reads 101010111001, exactly twelve bits, one for each switch, because the converter's three-bit mapping is what produces a pattern the panel can take. Because the first digit is 5 rather than 0, no leading zeros are dropped, and the length matches the panel.
| Octal group | Binary | Switches up |
|---|---|---|
| 5 | 101 | 2 |
| 2 | 010 | 1 |
| 7 | 111 | 3 |
| 1 | 001 | 1 |
Before touching the hardware, Dana runs a sanity check against the manual's own limit: a 12-bit address space tops out at 77778 (4095 in decimal), and 52718 is 2745 in decimal, safely below it. The binary string also has to match, and 2048 + 512 + 128 + 32 + 16 + 8 + 1 = 2745 does.
The next action is concrete: counting switches from the left, Dana raises numbers 0, 2, 4, 6, 7, 8 and 11 and leaves the other five down, then presses the load key. The seven raised switches match the seven 1s in the string, and the panel lamps echo the same pattern back, which confirms the address was entered correctly the first time.
Octal to Binary with a Decimal Point
The direct route also handles a fractional octal number. Treat each side of the radix point separately, then keep the point where it was. For 27.38, the 2 becomes 010, the 7 becomes 111, and the 3 after the point becomes 011, giving 010111.011, or 10111.0112 once the leading zero is removed. As a check, 27.38 equals 23.375 in decimal, and 10111.0112 equals 16 + 4 + 2 + 1 + 0.25 + 0.125 = 23.375.
Why Octal to Binary Conversion Still Matters in Computing
Octal grew popular in early computing because machines with 6-bit, 12-bit and 36-bit word sizes split cleanly into three-bit groups, so one symbol stood in for three bits and made long strings readable. That is the legacy computing link between the two bases: octal works as an abbreviation of binary.
Modern 16-, 32- and 64-bit systems divide evenly into four-bit groups, so hexadecimal replaced octal in most programming. Octal survives in a few places, though. Unix file permissions are written as octal digits such as 755 or 644, and each one expands to three permission flags (read, write, execute). Anyone working with minicomputers, embedded electronics or old computer systems documentation will still meet it, and the same number conversion skills carry over to a base converter for hex.
A quick chart in your head helps: 4 means read, 2 means write, 1 means execute, so 7 is 111 and 5 is 101. That is the same three-bit mapping the converter applies to any octal input.
Convert Octal to Binary: Solved Examples and Practice Problems
Try these on paper first, then confirm each one with the octal to binary converter. The solved examples show the expected answer for each problem.
- 27508: 010 111 101 000, so the answer is 101111010002.
- 52068: 101 010 000 110, so the answer is 1010100001102.
- 72148: 111 010 001 100, so the answer is 1110100011002.
Common Mistakes to Avoid
Most errors come from the same few slips. Entering an 8 or a 9 is invalid, since neither belongs to base 8. Writing a two-bit group such as 11 instead of 011 shifts every bit that follows. And reading the remainders from the top down flips the answer when you use the indirect route. Finally, do not strip zeros from the middle of a string: only the zeros at the very front are safe to drop, and every group in the middle must keep all three bits so the length stays a multiple of three. If a check fails, redo the lookup one digit at a time and compare each group against the table before you trust the output.